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## Inverse Cotangent of a Surd

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### Inverse Cotangent of a Surd

Wed Jan 25, 2017 1:40 pm

Posts: 27
Prove:

$$\displaystyle \huge \int_0^\frac{\pi}{2} \cot^{-1}{\sqrt{1+\csc{\theta}}} \, \text{d}\theta = \frac{\pi^2}{12}$$