Board index Computation of Integrals Inverse Cotangent of a Surd

## Inverse Cotangent of a Surd

Post your questions related to Computation of Integrals here.

Moderators: galactus, Random Variable, sos440

### Inverse Cotangent of a Surd

Wed Jan 25, 2017 1:40 pm

Posts: 27
Prove:

$$\displaystyle \huge \int_0^\frac{\pi}{2} \cot^{-1}{\sqrt{1+\csc{\theta}}} \, \text{d}\theta = \frac{\pi^2}{12}$$

### Re: Inverse Cotangent of a Surd

Fri Apr 07, 2017 8:41 pm

Posts: 85
If you know the solution, could you give a hint?